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6.28x^2=120
We move all terms to the left:
6.28x^2-(120)=0
a = 6.28; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·6.28·(-120)
Δ = 3014.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3014.4}}{2*6.28}=\frac{0-\sqrt{3014.4}}{12.56} =-\frac{\sqrt{}}{12.56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3014.4}}{2*6.28}=\frac{0+\sqrt{3014.4}}{12.56} =\frac{\sqrt{}}{12.56} $
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